Every once in awhile somebody asks me how to log off a dead user. This is how you discover the inactive session using the
21:00:01 up 78 days, 2:41, 2 users, load average: 0.08, 0.02, 0.75 USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT root pts/0 213-142-142-014. 20:55 0.00s 0.03s 0.00s w root pts/1 184.108.40.206 Mon11 3days 2days 0.03s -bash
You can easily spot the idle user by looking at the IDLE column; the user in the first row has been idle for 3 days. There are many ways of killing idle users, but here I’ll show you my favorite one. The bottom line is, you need to kill the parent process created by the idle user when he logged in.
Looking at the output from the
w command above, we can see that the idle users’ TTY is pts/1 so now all we need is the PID for the parent process. We can find that by running
who -all | grep root
Here we can see that 31472 is the PID for the parent process of pts/1, so once we issue
kill -1 31472 that idle session will be gone!
root + pts/0 2012-08-02 20:55 . 17366 (213-142-142-014.reverse.adeox.com) root + pts/1 2012-07-30 11:49 old 31472 (220.127.116.11)